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EddyCZ

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Oct 17th, 2023
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C 1.20 KB | None | 1 0
  1. #include <stdio.h>
  2.  
  3. void sub_3006() {
  4.     // Implement the logic of the sub_3006 function here.
  5. }
  6.  
  7. int sub_676() {
  8.     int R2 = 0; // Assuming R2 is initialized to 0
  9.     int R3, R4, R5, R0;
  10.  
  11.     R2 = -(SP);
  12.     R3 = -(SP);
  13.     R4 = -(SP);
  14.     R5 = -(SP);
  15.  
  16.     // Call a function located at the address in R4 (loc_3662+2)
  17.     // You'll need to provide an equivalent function call here.
  18.  
  19.     // loc_360: swab -(R2)
  20.     R2 = (short)(R2 & 0xFF) << 8 | (R2 >> 8);
  21.  
  22.     // loc_362: mov (SP)+, R4
  23.     R4 = *(int *)SP;
  24.  
  25.     // Call sub_3006 function
  26.     sub_3006();
  27.  
  28.     // loc_370: swab @-(R2)
  29.     int address = R2;
  30.     R2 = (short)(R2 & 0xFF) << 8 | (R2 >> 8);
  31.     R2--;
  32.     R2 = (short)(R2 & 0xFF) << 8 | (R2 >> 8);
  33.  
  34.     // loc_372: mov (SP)+, R4
  35.     R4 = *(int *)SP;
  36.  
  37.     // loc_374: mov (R5)+, R3
  38.     R3 = *(int *)R5;
  39.     R5 += 2;
  40.  
  41.     // loc_376: mov (R5)+, R1
  42.     R1 = *(int *)R5;
  43.     R5 += 2;
  44.  
  45.     // Start of function chunk for sub_676
  46.     // You will need to translate the remaining code for sub_676 here.
  47.  
  48.     return 0; // Assuming sub_676 returns an integer value.
  49. }
  50.  
  51. int main() {
  52.     int result = sub_676();
  53.     // Implement the rest of your program here.
  54.     return 0;
  55. }
  56.  
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