Counting number of +ve,-ve and non-zero terms

#include <stdio.h>
int count=0,p=0,n=0;
void nzero()
{
    count++;
}
void positive()
{
    p++;
}
void negative()
{
    n++;
}

int main()
{
    int num, choice = 1;
    do
    {
        printf("Enter a number.");
        scanf("%d",&num);
        if(num!=0)
        {
            nzero();
            if(num>0)
                positive();
            else
                negative();
        }
        printf("Do you want to enter more? 1.Yes 2.No: ");
        scanf("%d",&choice);
    } while (choice!=2);
    printf("\nNumber of non-zero numbers: %d\n",count);
    printf("Number of positive numbers: %d\n",p);
    printf("Number of negative numbers: %d\n",n);
    return 0;
}
//Output
//Enter a number.-2
//Do you want to enter more? 1.Yes 2.No: 1
//Enter a number.0
//Do you want to enter more? 1.Yes 2.No: 1
//Enter a number.34
//Do you want to enter more? 1.Yes 2.No: 2

//Number of non-zero numbers: 2
//Number of positive numbers: 1
//Number of negative numbers: 1