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Encode infinite number of dimensions of numbers to one number
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- X = (y * 2 - 1) * (2^z) solve for z and y given x
- z = log2(x / y * 2 - 1)
- y = (X / (2 ^ z) + 1 / 2)
- z = log2(x / (x / (2 ^ z) + 1 / 2) * 2 - 1)
- y = (x / (2 ^ z) + 1 / 2)
- z = log2(x / (X / (2 ^ log2(x / (X / (2 ^ z) + 1 / 2) * 2 - 1)) + 1 / 2) * 2 - 1)
- z = log2(x / (X / (2 ^ log2(x / (X / (2 ^ log2(x / (X / (2 ^ z) + 1 / 2) * 2 - 1)) + 1 / 2) * 2 - 1)) + 1 / 2) * 2 - 1)
- x = ((((y * 2 - 1) * (2^z)) * 2 - 1) * (2^e)) solve for z and y and e given x
- z = log2((((X / (2^e) + 1) / 2) / (2^z) + 1) / (2 * ((((X / (2^e) + 1) / 2) / (2^z) + 1) / 2)))
- y = (((X / (2^e) + 1) / 2) / (2^z) + 1) / 2
- e = log2((((X / (2^e) + 1) / 2) / (2^z) + 1) / (2 * y))
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