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esraa_syam

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Mar 26th, 2023
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C++ 2.50 KB | None | 0 0
  1. #include<bits/stdc++.h>
  2. #define nl "\n"
  3. #define fi first
  4. #define se second
  5. #define pi 3.14159
  6. #define ll long long
  7. #define odd(a)  (a&1)
  8. #define even(a)  !(a&1)
  9. #define Mod 1'000'000'007
  10. #define INF 2'000'000'000
  11. #define sz(x) int(x.size())
  12. #define charToInt(s) (s - '0')
  13. #define ull unsigned long long
  14. #define number_line iota(all(vec) , 1)
  15. #define all(s) s.begin(), s.end()
  16. #define rall(v) v.rbegin() , v.rend()
  17. #define fixed(n) fixed << setprecision(n)
  18. #define Num_of_Digits(n) ((int)log10(n) + 1)
  19. #define to_decimal(bin) stoll(bin, nullptr, 2)
  20. #define Ceil(n, m) (((n) / (m)) + ((n) % (m) ? 1 : 0))
  21. #define Floor(n, m) (((n) / (m)) - ((n) % (m) ? 0 : 1))
  22. #define Upper(s) transform(all(s), s.begin(), ::toupper);
  23. #define Lower(s) transform(all(s), s.begin(), ::tolower);
  24. #define cout_map(mp) for(auto& [f, s] : mp) cout << f << "  " << s << "\n";
  25. //  ----- bits-------
  26. #define pcnt(n) __builtin_popcount(n)  
  27. #define pcntll(n) __builtin_popcountll(n)
  28. #define clz(n) __builtin_clz(n)    // <---100
  29. #define clzll(n) __builtin_clzll(n)
  30. #define ctz(n) __builtin_ctz(n)  // 0001---->
  31. #define ctzll(n) __builtin_ctzll(n)
  32.  
  33. using namespace std;
  34.  
  35. template < typename T = int > istream& operator >> (istream &in, vector < T > & v){
  36.     for(auto & x : v) in >> x;
  37.     return in;
  38. }
  39.  
  40. template < typename T = int > ostream& operator << (ostream &out, const vector < T > & v){
  41.     for(const T & x : v) out << x << " ";
  42.     return out;
  43. }
  44.  
  45. void esraa()
  46. {
  47.     ios_base::sync_with_stdio(false), cin.tie(nullptr), cout.tie(nullptr);
  48. #ifndef ONLINE_JUDGE
  49.     freopen("input.txt", "r", stdin), freopen("output.txt", "w", stdout);
  50. #endif
  51. }
  52. vector < pair < int , pair < int , int > > > v;
  53. int n , r_a , r_b;
  54. int rec(int idx , int cost , int sum_a , int sum_b){
  55.     // cout << idx << " " << cost << " " << sum_a << " " << sum_b << nl;
  56.     if(idx == n - 1){
  57.         if(sum_a * r_b == sum_b * r_a and sum_a and sum_b) return cost;
  58.         return INF;
  59.     }
  60.     int ret1 = rec(idx + 1 , cost , sum_a , sum_b);
  61.     int ret2 = rec(idx + 1 , cost + v[idx].se.se , sum_a + v[idx].fi , sum_b + v[idx].se.fi);
  62.     return min(ret1 , ret2);
  63. }
  64. void solve(){
  65.     cin >> n >> r_a >> r_b;
  66.     v.resize(n);
  67.     ll sum = 0;
  68.     for(int i = 0 ; i < n ; i++){
  69.         cin >> v[i].fi >> v[i].se.fi >> v[i].se.se;
  70.         sum += v[i].se.se;
  71.     }
  72.    
  73.     cout << rec(0 , 0 , 0 , 0) << nl;
  74. }
  75. int main()
  76. {
  77.     esraa();
  78.     int t = 1;
  79.     //cin >> t;
  80.     //cin.ignore();
  81.     while(t--)
  82.       solve();
  83.     return 0;
  84. }  
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