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Korotkodul

N2

Nov 15th, 2022 (edited)
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C++ 1.97 KB | None | 0 0
  1. #include <iostream>
  2. #include <cmath>
  3. #include <vector>
  4. #include <queue>
  5. #include <algorithm>
  6. #include <string>
  7. #include <stack>
  8. #include <set>
  9. #include <map>
  10. #define pii pair <int, int>
  11. #define pb(x) push_back(x)
  12. using namespace std;
  13. using ll = long long;
  14. using ld = long double;
  15. using db = double;
  16. void cv(vector <int> &v) {
  17.     for (auto x : v) cout << x << ' ';
  18.     cout << "\n";
  19. }
  20.  
  21. void cvl(vector <ll> &v) {
  22.     for (auto x : v) cout << x << ' ';
  23.     cout << "\n";
  24. }
  25.  
  26.  
  27. void cvv(vector <vector <int> > &v) {
  28.     for (auto x : v) cv(x);
  29.     cout << "\n";
  30. }
  31.  
  32. void cvb(vector <bool> v) {
  33.     for (bool x : v) cout << x << ' ';
  34.     cout << "\n";
  35. }
  36.  
  37. void cvs(vector <string>  v) {
  38.     for (auto a : v) {
  39.         cout << a << "\n";
  40.     }
  41. }
  42.  
  43. void cvp(vector <pii> a) {
  44.     for (auto p : a) {
  45.         cout << p.first << ' ' << p.second << "\n";
  46.     }
  47.     cout << "\n";
  48. }
  49.  
  50. bool sh = 0;
  51. /*
  52. 3 1 2
  53. -2 10 100
  54. */
  55. int main() {
  56.     ios::sync_with_stdio(0);
  57.     cin.tie(0);
  58.     cout.tie(0);
  59.     ll n, k, p;
  60.     cin >> n >> k >> p;
  61.     vector <ll> a(n + 2), dp(n + 2, -1);
  62.     a[0] = 0;
  63.     a[n + 1] = 0;
  64.     dp[0] = p;
  65.     for (int i = 1; i <= n; ++i) {
  66.         cin >> a[i];
  67.     }
  68.     if (sh) {
  69.         cout << "n k p = " << n << ' ' << k << ' ' << p << "\n";
  70.         cout << "a\n"; cvl(a);
  71.     }
  72.     for (ll i = 1; i <= n + 1; ++i) {
  73.         if (sh) {
  74.             cout << "i = " << i << "\n";
  75.             cout << "dp\n"; cvl(dp);
  76.             cout << "i - k  = " << i - k << "\n";
  77.         }
  78.         for (ll j = max(0LL, i - k); j <= i - 1; ++j) {
  79.             if (sh) {
  80.                 cout << "j =  " << j << "\n";
  81.             }
  82.             if (dp[j] < 0) {
  83.                 continue;
  84.             }
  85.             dp[i] = max(dp[i], dp[j] + a[i]);
  86.         }
  87.     }
  88.     if (sh) {
  89.         cout << "a\n"; cvl(a);
  90.         cout << "dp\n"; cvl(dp);
  91.     }
  92.     if (dp[n + 1] < 0 ) {
  93.         cout << -1;
  94.         exit(0);
  95.     }
  96.     cout << dp[n + 1];
  97. }
  98.  
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