python

# 1 Вариант 15
from math import sin


def main(x):
    return ((x**5 - (x**3 / 24)) / ((x**3 + 31 + x)**3/19)
            + (56 * x**3 - x**2) / (84 * sin(x)**4 - 43 * x**5))


# 2 Вариант 15
from math import ceil, floor


def main(x):
    a = [
        74 * abs(x) ** 7 + 77 * x ** 9 + 83 * (x / 38) ** 6,
        floor(x ** 3 + x ** 2 + x) ** 7,
        (ceil(x) ** 4) / 12 - 1 - 5 * (0.01 - x - 9 * x ** 2) ** 2
    ]
    if x < 68:
        return a[0]

    if 68 <= x < 83:
        return a[1]

    if x >= 83:
        return a[2]

    # Или код нижу(второй способ решения)

    # a = 74 * abs(x)**7 + 77 * x**9 + 83 * (x / 38)**6
    # b = floor(x**3 + x**2 + x)**7
    # c = (ceil(x)**4) / 12 - 1 - 5 * (0.01 - x - 9 * x**2)**2
    # return a if x < 68 else b if 68 <= x < 83 else c


# 3 Вариант 15
def func(i, k, j, y):
    return 81 * ((j**3 + 2 * i**2)**7) - ((y - 63)**6) - 88 * k


def main(b, n, a, y, i=1, k=1, j=1):
    if i > a:
        return 0
    if j > b:
        return main(b, n, a, y, i+1)
    if k > n:
        return main(b, n, a, y, i, 1, j+1)
    return func(i, k, j, y) + main(b, n, a, y, i, k+1, j)


# 4 Вариант 15
def main(n):
    ans = [0.92, 0.15]
    ans.extend(1 - 10 * ans[i-2] - ans[i-1] for i in range(2, n+1))
    # extend меняет элемент "на месте" то есть не сохраняет изменения
    print(ans)
    return ans[n]


# 5 Вариант 15
import math


def func(i, n, x):
    return 0.03 + ((x[len(x) + 1 - math.ceil(i / 3)
                    - 1] ** 3) / 20) + 87 * (x[i-1] ** 2)


def main(x, i=1):
    n = len(x)
    if i > n:
        return 0.0
    return func(i, n, x) + main(x, i+1)


# 6 Вариант 15
def calculate_1(B):
    N = set()
    Xi = set()

    for b in B:
        if -82 <= b < 63:
            N.add(b)
        if b > -56 or b <= 58:
            Xi.add(b * 6)

    return N, Xi


def calculate_2(Xi):
    E = set()
    absolute_sum = 0

    for e in Xi:
        if e <= -5 or e > -58:
            E.add(e + e % 3)
            absolute_sum += abs(e + e % 3)

    return E, absolute_sum


def main(B):

    N, Xi = calculate_1(B)
    E, absolute_sum = calculate_2(Xi)

    return len(N | E) - absolute_sum


# 7 Вариант 15
def two(x, left, right):
    if x[2] == 'HYPHY':
        return left
    if x[2] == 'GAP':
        return right


def one(x, left, middle, right):
    if x[1] == 2019:
        return left
    if x[1] == 1981:
        return right
    if x[1] == 1965:
        return middle


def four(x, left, middle, right):
    if x[4] == 'SQLPL':
        return left
    if x[4] == 'NUMPY':
        return middle
    if x[4] == 'MESON':
        return right


def main(x):
    if x[0] == 1979:
        return four(x, one(x, 0, two(x, 1, 2), 3), 4, two(x, 5, 6))
    if x[0] == 1997:
        return 7
    if x[0] == 1959:
        return one(x, four(x, two(x, 8, 9), 10, 11), 12, 13)


# 8 Вариант 15
def main(number):
    num = int(number)

    c1 = (num >> 0) & 0b1
    c2 = (num >> 1) & 0b11
    c3 = (num >> 3) & 0b1111_1111_11
    c4 = (num >> 13) & 0b1111_1111
    c5 = (num >> 21) & 0b1111_1111
    # 0b1111_1111 == 0b11111111 "_" - это разделитель для удобства
    result = int((c5 << 21) | (c1 << 20) | (c3 << 10) | (c4 << 2) | (c2 << 0))

    return result


# 9 Вариант 15
def main(a):
    ans = {}
    sep = a.split(".end;")
    for value in sep:
        if "declare" in value:
            part = value.split("declare")
            if len(part) > 1:
                key = part[1].split("<==")[0].strip().replace('"', '')
                ans_var = part[1].split("<==")[1].strip().replace('#', '')
                ans[key] = int(ans_var)
    return ans

# 10 Вариант 15
def for1(a):
    b = [i for i in a if i.count(None) != 5]
    return b


def for2(a):
    b = [[i for i in j if i is not None] for j in a]
    return b


def if1(i):
    if '/' in i[0]:
        i[0] = i[0].replace('/', '-')
    return i


def if2(i):
    if '-' in i[2]:
        i[2] = '-'.join(i[2].split('-')[1:])
    return i


def if3(i):
    if i[1] == '1':
        i[1] = 'Выполнено'
    if i[1] == '0':
        i[1] = 'Не выполнено'
    return i


def for3(a):
    return [if1(if2(if3(i))) for i in a]


def for4(a):
    b = [[i[j] for i in a] for j in range(len(a[0]))]
    return b


def main(a):
    b = for1(a)
    a = for2(b)
    a = for3(a)
    b = for4(a)
    return b


# a = [[None, None, None, None, None], [None, None, None, None, None], [None, None, '00/07/16', '1', '292-716-7694'], [None, None, '03/02/23', '0', '844-437-4569'], [None, None, '01/02/23', '1', '483-462-8067']]
# print(main(a))