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Korotkodul

швб_22-23_N3

Oct 23rd, 2022 (edited)
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C++ 1.81 KB | None | 0 0
  1. #include <iostream>
  2. #include <cmath>
  3. #include <vector>
  4. #include <queue>
  5. #include <algorithm>
  6. #include <string>
  7. #include <stack>
  8. #include <set>
  9. #include <map>
  10. #define pii pair <int, int>
  11. #define pb(x) push_back(x)
  12. using namespace std;
  13. using ll = long long;
  14. using ld = long double;
  15. using db = double;
  16. void cv(vector <int> &v) {
  17.     for (auto x : v) cout << x << ' ';
  18.     cout << "\n";
  19. }
  20.  
  21. void cvl(vector <ll> &v) {
  22.     for (auto x : v) cout << x << ' ';
  23.     cout << "\n";
  24. }
  25.  
  26.  
  27. void cvv(vector <vector <int> > &v) {
  28.     for (auto x : v) cv(x);
  29.     cout << "\n";
  30. }
  31.  
  32. void cvb(vector <bool> v) {
  33.     for (bool x : v) cout << x << ' ';
  34.     cout << "\n";
  35. }
  36.  
  37. void cvs(vector <string>  v) {
  38.     for (auto a : v) {
  39.         cout << a << "\n";
  40.     }
  41. }
  42.  
  43. void cvp(vector <pii> a) {
  44.     for (auto p : a) {
  45.         cout << p.first << ' ' << p.second << "\n";
  46.     }
  47.     cout << "\n";
  48. }
  49.  
  50. bool sh = 0;
  51.  
  52. int main() {
  53.     ios::sync_with_stdio(0);
  54.     cin.tie(0);
  55.     cout.tie(0);
  56.     int n; cin >> n;
  57.     vector <int> a(n), pf(n);
  58.     for (int &i: a) cin >> i;
  59.     if (n < 3) {
  60.         cout << 0;
  61.         exit(0);
  62.     }
  63.     pf[0] = a[0];
  64.     for (int i = 1; i < n; ++i) {
  65.         pf[i] = pf[i - 1] + a[i];
  66.     }
  67.     if (sh) {
  68.         cout << "a pf\n";
  69.         cv(a);
  70.         cv(pf);
  71.     }
  72.     for (int i = 0; i <= n - 2; ++i) {
  73.         for (int j = i + 1; j <= n - 2; ++j) {
  74.             int a, b, c;
  75.             a = pf[i];
  76.             b = pf[j] - pf[i];
  77.             c = pf[n - 1] - pf[j];
  78.             if (a == b && a == c) {
  79.                 int l1 = i + 1, l2 = j - i, l3 = n - 1 - j;
  80.                 int ans = max(l1, l2);
  81.                 ans = max(ans, l3);
  82.                 cout << ans;
  83.                 exit(0);
  84.             }
  85.         }
  86.     }
  87.     cout << 0;
  88. }
  89. /*
  90. 5
  91. 1 1 1 1 2
  92. */
  93.  
  94.  
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