02. Equal Sums Even Odd Position

function equalSumsEvenOddPosition(input) {
    let num1 = Number(input[0]);
    let num2 = Number(input[1]);
    let output = "";

    for (let i = num1; i <= num2; i++) {
        let odd = 0;
        let even = 0;
        let digit = i;

        for (let x = 0; x < 6; x++) {
            if (x % 2 === 0) {
                even += digit % 10;
            } else {
                odd += digit % 10;
            }
            digit = Math.floor(digit / 10);
        }
        if (odd === even) {
            output += i + " ";
        }
    }
    console.log(output)
}


РЕШЕНИЕ С toString():

function  equalSumsEvenOddPosition(input) {
    let num1 = Number(input[0]);
    let num2 = Number(input[1]);
    let output = "";

    for (let i = num1; i <= num2; i++) {
        let odd = 0;
        let even = 0;
        let current = i.toString();

        for (let x = 0; x < current.length; x++) {
            let digit = Number(current[x].toString());
            if (x % 2 === 0) {
                even += digit;
            } else {
                odd += digit;
            }
        }
        if (odd === even) {
            output += i + " ";
        }
    }
    console.log(output)
}