laba3_1

    include 'MACRO\PROC32.INC' ;for PROC-ENDP

    org 100h

    NL_ equ 0dh, 0ah ;const

    mov ah, 09h ;output - helloStr
    mov dx, helloStr_
    int 21h

    mov dx, inputStr_ ;output - inputStr
    int 21h

    mov ah, 0ah ;input to buff
    mov dx, buffNum
    int 21h

    add dx, 2 ;dx to the first char of number
    call str_to_int_ ;input dx - string that ends on 0dh, output al - 8 bit number
    mov bh, al ;save first number to bh

    mov ah, 02h ;output - new line
    mov dx, 0d0ah
    int 21h

    mov ah, 09h ;output - inputStr
    mov dx, inputStr_
    int 21h

    mov ah, 0ah ;input to buff
    mov dx, buffNum
    int 21h

    add dx, 2 ;get second number
    call str_to_int_

    mov dl, al ;save second to dl
    mov dh, bh ;move first to dh

    call task_ ;input dh:dl - two numbers, output ax - 16 bit number

    mov dx, buffAns
    call int_to_str_ ;input ax - 16 bit number, dx - 6 byte buffer; output - string representation of number in buff that ends with $

    mov ah, 09h ;output - resultStr
    mov dx, resultStr_
    int 21h

    mov dx, buffAns ;output - buffAns
    int 21h

    mov dx, byeStr_ ;output - byeStr
    int 21h

    mov ah, 08h ;wait for input
    int 21h
    ret

proc str_to_int_ ;input dx - string that ends on 0dh; output al - 8bit number
    push dx ;save
    push ax ;save
    push bx ;save
    mov bx, dx ;memory accessible only from bx
    xor dx, dx ;clear dx
    next_digit_:
        mov ax, 10 ;10 to ax
        mul dh ;multiplied by 1 byte; result ah:al
        mov dh, al ;move result of multiolication to dh
        mov dl, byte [bx] ;move one SYMBOL to dl
        sub dl, '0' ;convert SYMBOL to NUMBER 0-9
        add dh, dl ;add dl to dh
        inc bx ;move to next symbol
        cmp byte [bx], 0dh ;are we at the last symbol?
        jne next_digit_ ;if no then there're still numbers to convert left
    pop bx ;retrieve
    pop ax ;retrieve
    mov al, dh ;save 8bit answer to al
    pop dx ;retrieve
    ret ;go back
    endp

proc int_to_str_ ;input ax - 16 bit number, dx - 6 byte buffer; output - string representation of number in buff that ends with $
    push ax ;save ...
    push dx
    push bx
    push si ;memory is also accessible at bx+si
    push bp
    mov bp, sp ;move sp to bp
    sub sp, 5 ;reserve 5byte of stack
    mov word [bp-2], dx ;save address of buff
    mov word [bp-4], 10 ;in first two byte save constant 10
    mov byte [bp-5], 1 ;in third byte save AMOUNT of letters in the number, as it at least has '$' counter starts from 1
    xor dx, dx
    mov bx, word [bp-2] ;memory accessible from bx only...
    mov byte [bx], '$' ;this is the first letter
    next_letter_:
        inc bx ;move to next letter
        add byte [bp-5], 1 ;increment AMOUNT of letters
        div word [bp-4] ;divide dx:ax by 16bit number; result dx-remainder, ax-quotient
        add dl, '0' ;convert to ascii number
        mov [bx], dl ;save that letter
        xor dx, dx ;clear dx
        cmp ax, 0 ;have we converted whole number?
        jne next_letter_ ;if no there're still number to convert
    xor si, si ;clear si
    mov si, [bp-5] ;move two bytes of reserved stack to si: lowest - [bp-3], highest - [bp-2] (little-endian)
    and si, 00ffh ;clear highest byte, only AMOUNT left in si
    dec si ;get offset to the LAST letter from FIRST
    mov al, [bp-5] ;amount to al, ah is zero
    shr ax, 1 ;divide by 2 as integer (for i = 0 to i / 2), "i/2" - integer division, so we get amount of swaps needed to reverse a string
    mov [bp-5], al ;save that number to [bp-2]
    mov bx, [bp-2] ;restore position of the FIRST letter
    next_switch_:
        mov ah, [bx] ;swap two letters using ax...
        mov al, [bx + si]
        mov [bx], al
        mov [bx+si], ah
        inc bx ;move to next letter
        sub si, 2 ;as si is OFFSET to last letter, not index, subtract 2 to get OFFSET to (last-1) letter
        sub byte [bp-5], 1 ;amount of swaps - 1
        cmp byte [bp-5], 0 ;have we finished?
        jne next_switch_ ;no? go back!
    mov sp, bp ;return stack pointer to its original state
    pop bp ;retrieve data...
    pop si
    pop bx
    pop dx
    pop ax
    ret ;go back
    endp

proc task_ ;input dh:dl - two numbers, output ax - 16 bit number
    xor ax, ax ;clear ax
    mov al, dl ;first number...
    mul dh ;...multiplied by second, 8bit*8bit=16bit => result in ax
    shl ax, 1 ;multiply by 2
    sub ax, 3 ;subtract 3
    ret ;go back
    endp

helloStr_ db "This program calculates the result of 2*x*y-3", NL_, "Using register type procedure", NL_, "$"
inputStr_ db "Input number in range from 0 to 254:", NL_, "$"
resultStr_ db NL_, "Result:", NL_, "$"
byeStr_ db NL_, "The program has now terminated. Press anything to continue...$"
buffNum db 4, 0, 4 dup(?)
buffAns db 6 dup (?)