t2

/*
Complete the method to return true when its argument is an array
that has the same nesting structures and same corresponding
length of nested arrays as the first array.

For example:
 // should return true
[ 1, 1, 1 ].sameStructureAs( [ 2, 2, 2 ] );
[ 1, [ 1, 1 ] ].sameStructureAs( [ 2, [ 2, 2 ] ] );

 // should return false
[ 1, [ 1, 1 ] ].sameStructureAs( [ [ 2, 2 ], 2 ] );
[ 1, [ 1, 1 ] ].sameStructureAs( [ [ 2 ], 2 ] );

// should return true
[ [ [ ], [ ] ] ].sameStructureAs( [ [ [ ], [ ] ] ] );

// should return false
[ [ [ ], [ ] ] ].sameStructureAs( [ [ 1, 1 ] ] );
*/

Array.prototype.sameStructureAs = function (arr) {
  if(arr.length !== this.length) return false;

  for(let i = 0; i < arr.length; i++){
    if(Array.isArray(arr[i]) && Array.isArray(this[i])){
      if(!this[i].sameStructureAs(arr[i])) return false;
      continue;
    }

    if(Array.isArray(arr[i]) || Array.isArray(this[i])){
      return false;
    }
  }

  return true;
}


console.log([ 1, 1, 1 ].sameStructureAs( [ 2, 2, 2 ] )); // true
console.log([ 1, [ 1, 1 ] ].sameStructureAs( [ 2, [ 2, 2 ] ] )); // true
console.log([ 1, [ 1, 1 ] ].sameStructureAs( [ [ 2, 2 ], 2 ] ));  // false
console.log([ 1, [ 1, 1 ] ].sameStructureAs( [ [ 2 ], 2 ] ));  // false
console.log([ [ [ ], [ ] ] ].sameStructureAs( [ [ [ ], [ ] ] ] )); // true
console.log([ [ [ ], [ ] ] ].sameStructureAs( [ [ 1, 1 ] ] )); // false