DEBUUUUUUUGV2

int d[300000], q[(int)(1e7 * 1.1)], h, t, pr[300000];
vector<vector<pair<int, pair<bool, bool> > > > g(200001);// , g1(200001);
vector<bool> debt(N), used(N);
set<pair<int, int> > us;

int add(int a, int b)
{
    if (a == -1 || b == -1) return -1;
    else return ((a + b) % mod);
}

int main()
{
    d[0] = 1;
    int n, m, a, b, v;
    cin >> n >> m;
    for (int i = 0; i < m; i++)
    {
        scanf("%d%d", &a, &b);
        a--;
        b--;
        g[a].pb(mp(b, mp(0, 0)));
        pr[b]++;
    }
    q[h++] = 0;
    used[0] = 1;
    for (; h != t;)
    {
        v = q[t++];
        t %= md;
        for (vector<pair<int, pair<bool, bool> > >::iterator i = g[v].begin(); i != g[v].end(); i++)
        {
            if (i->yy.xx)
            {
                d[i->xx] = d[v] = pr[i->xx] = pr[v] = -1;
                debt[v] = 1;
                continue;
            }
            else i->yy.xx = 1;
            if (pr[v] <= 0)
            {
                d[i->xx] = add(d[i->xx], d[v]);
                pr[i->xx]--;
                //debt[v] = 1;
                if (!used[i->xx])
                {
                    q[h++] = i->xx;
                    h %= md;
                    used[i->xx] = 1;
                    debt[v] = 0;
                }
            }
            else
            {
                debt[v] = 1;
                q[h++] = i->xx;
                h %= md;
            }
        }
    }
    h = t = 0;
    q[h++] = 0;
    used[0] = 1;
    for (; h != t;)
    {
        v = q[t++];
        t %= md;
        if (pr[v] > 0)
        {
            q[h++] = v;
            h %= md;
            continue;
        }
        for (vector<pair<int, pair<bool, bool> > >::iterator i = g[v].begin(); i != g[v].end(); i++)
        {
            if (debt[v]) d[i->xx] = add(d[i->xx], d[v]), pr[i -> xx]--;
            if (!(i->yy.yy))
            {
                q[h++] = i->xx;
                h %= md;
                i->yy.yy = 1;
                pr[i->xx]--;
            }
        }
        debt[v] = 0;
    }
    for (int i = 1; i < n; i++) printf("%d\n", d[i]);
    return 0;
}