one line Anagram detector (Explained)

isAnagram = lambda s1,s2 : False if False in map(lambda i: i in s1, s2) else True

print isAnagram("Hello", "ebola") # False
print isAnagram("Hello", "olelH") # True

#### EXPLAINING BEGINS ####

# def isAnagram(s1,s2):
##Taking two arguments: s1, and s2, both being strings.

#return False if False in ... else True
##A clever one line solution as opposed to typing the following:

#if False in ...:
#    return False
#else:
#    return True

#map(lambda i: i in s1, s2)
#...

    #lambda i: i in ...
    ##lambda is basically an on-the-go version of 'def' where 'i' is the argument of the function
    ##You should know that 'x in y' returns True or False. This lambda function is basically saying:
    #def function(i, ...):
    #    if i in ...:
    #        return True
    #    else:
    #        return False

    #map(..., s2)
    ##This is basically a 'zip()' but for functions.
    ##It replaces the letters in s2 with the output of the 'lambda' function(which returns True or False).

#Now for an intentionally longer version...


def isAnagram(s1, s2):

    confirmation = [] #blank list for later

    for i in s2:   #iterate over s1

        if i in s2:

            confirmation.append(True)

        else:

            confirmation.append(False)

    if True in confirmation:

        return True

    else:

        return False



#A shorter version:

def isAnagram2(s1, s2):

    confirmation = [] #blank list for later

    for i in s2:   #iterate over s1

        if i in s2:

            confirmation.append(True)

    if len(confirmation) > 0:  #True was the only thing we could have oppended to it
    #So logically...

        return True

    else:

        return False