02. English Name of the Last Digit

import java.util.Scanner;

class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int n = Integer.parseInt(scanner.nextLine()) % 10;

        String result = switch (n) {
            case 1 -> "one";
            case 2 -> "two";
            case 3 -> "three";
            case 4 -> "four";
            case 5 -> "five";
            case 6 -> "six";
            case 7 -> "seven";
            case 8 -> "eight";
            case 9 -> "nine";
            default-> "zero";
        };

        System.out.println(result);
    }
}

Solutions with ternary operator:

import java.util.Scanner;

class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int n = Integer.parseInt(scanner.nextLine()) % 10;

        String result =
            n == 1 ? "one":
            n == 2 ? "two":
            n == 3 ? "three":
            n == 4 ? "four":
            n == 5 ? "five":
            n == 6 ? "six":
            n == 7 ? "seven":
            n == 8 ? "eight":
            n == 9 ? "nine" : "zero";

        System.out.println(result);
    }
}

Solution with array:

import java.util.Scanner;

class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int n = Integer.parseInt(scanner.nextLine()) % 10;

        String[] numbers = {
            "zero",
            "one",
            "two",
            "three",
            "four",
            "five",
            "six",
            "seven",
            "eight",
            "nine"
        };

        System.out.println(numbers[n]);
    }
}