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- Так же разложим:
- $$\left\{\begin{array}{l}x+3\ge 0\\ 49+4x-{x}^{2}={\left(x+3\right)}^{2}\end{array}\right.\Rightarrow \left\{\begin{array}{l}x\ge -3\\ 2{x}^{2}+2x-40=0\end{array}\right.\Rightarrow \left\{\begin{array}{l}x\ge -3\\ x=-5;4\end{array}\right.\Rightarrow x=4$$
- Ответ:
- 4
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