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- #include <bits/stdc++.h>
- using namespace std;
- typedef long long LL;
- typedef long double ld;
- const int MX=1e5+9;
- pair<LL,LL> dom[MX];
- int ar[MX],er[MX],n;
- map<pair<int,int>,int> dp;
- int solve(int st,int en)
- {
- if(st>en)return 0;
- if(dp[{st,en}]!=0)return dp[{st,en}]-1;
- int x=dom[st].first;
- int y=dom[st].second;
- int xx=dom[en].first;
- int yy=dom[en].second;
- int ans=0;
- // new st en or new en st
- int temp=x+y;
- int i;
- if(ar[st]!=-1)i=ar[st];
- else for( i=st;i<n;i++)
- {
- int ox,oy;
- ox=dom[i].first;
- oy=dom[i].second;
- if(temp>=ox)temp=max(temp,ox+oy);
- else break;
- }
- ar[st]=i;
- ans=1+solve(i,en);
- temp= xx-yy;
- if(er[en]!=-1)i=er[en];
- else for( i=en;i>=0;i--)
- {
- int ox,oy;
- ox=dom[i].first;
- oy=dom[i].second;
- if(temp<=ox)temp=min(temp,ox-oy);
- else break;
- }
- er[en]=i;
- ans=min(ans,1+solve(st,i));
- dp[{st,en}]=ans+1;
- return ans;
- }
- int main()
- {
- memset(er,-1,sizeof er);
- memset(ar,-1,sizeof ar);
- scanf("%d",&n);
- for(int i=0;i<n;i++)
- {
- scanf("%d%d",&dom[i].first,&dom[i].second);
- }
- sort(dom,dom+n);
- printf("%d",solve(0,n-1));
- return 0;
- }
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