#1)
def f(n):
    a = {}
    for i in range(len(n)):
        a[n[i]] = n[i]
    return a
n = [x for x in input().split()]
print(f(n))



# 2)
def f(n):
    a = {}
    for i in range(1, n + 1):
        a[i] = i ** 2
    return a


print(f(int(input())))

# 3)
a = {'data1': 375, 'data2': 567, 'data3': -37, 'data4': 21}
s = 1
for i in a:
    s *= a[i]
print(s)
#Ответ: -165209625


#4)
a  = {',','.',';',':','?','!'}
count = 0
s = input()
for i in range(len(s)):
    if s[i] in a:
        count += 1
print(count)
#Ответ: 1
#5)
a = {'0','1','2','3','4','5','6','7','8','9'}
b = []
s = input()
for i in range(len(s)):
    if s[i] in a:
        b.append(s[i])
if len(b) >= 1:
   s = set(b)
   b = list(s)
   b.sort()
   print(*b,sep='')

else:
    print('NO')