[OS] Find Shell Scripts

#!/bin/bash
if [ $# -ne 3 ]
then
    echo "USAGE: `basename $0` imenik bajti some_file.txt"
    exit 1
fi
if [ ! -d $1 ]
then
    echo "Imenikot prosleden kako argument ne postoi"
    exit 1
fi
#there should also be a check if the second argument is a number but I did not find that part enteratining so let's hope it's a number
file_name=`echo $3 | sed 's/\.txt//'`
if [ ! -f $3 ]
then
    touch $3
else
    rm $3
    touch ${file_name}_moved.txt
fi
#get all .sh files that weigh less than 150B from argument1 directory
SCRIPTS=`ls -R $1 | awk '$4<150 && $10~/\.sh$/ {print $10}'`
for script in $SCRIPTS
do
    #make sure they are executable by the user
    chmod $script u+x
    result=`./$script`
    #just tryna detect whether they require to be called with arguments or not
    #I know this segment looks kinda goofy but my hungry ass could not think of any other way atm
    #I am not sure whether we should learn that by the output message or like the exit call or something
    #if anyone knows more to it simply DM me :3
    temp=`$result | grep USAGE`
    if [ -f $3 ]
    then
        if [ "$result" == "$temp" ]
        then
            echo "$script se povikuva so argumenti" >> $3
        else
            echo "$script se povikuva bez argumenti" >> $3
    else
        if [ "$result" == "$temp" ]
        then
            echo "$script se povikuva so argumenti" >> ${file_name}_moved.txt
        else
            echo "$script se povikuva bez argumenti" >> ${file_name}_moved.txt
    fi
done
if [ -f $3 ]
then
    cat $3
else
    cat ${file_name}_moved.txt