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com1001correct.txt

Feb 9th, 2025
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  1. The operation used to toggle a specific bit#(a)XOR(b)AND(c)OR(d)NOT#a
  2. The result of ANDing 1 and 0 is#(a)0(b)1(c)10(d)11#a
  3. Which operation sets all bits to 0?#(a)XOR with 0(b)AND with 0(c)OR with 0(d)NOT#b
  4. What does left-shifting a binary number by 2 do?#(a)Divide by 2(b)Add 2(c)Multiply by 4(d)Subtract 2#c
  5. How many bits are in a nibble?#(a)8(b)2(c)4(d)16#c
  6. The binary representation of decimal 10 is#(a)1001(b)1010(c)1100(d)1110#b
  7. What is the result of ORing 1010 with 0101?#(a)1111(b)1010(c)0000(d)1000#a
  8. The complement of 1110 is#(a)0000(b)1111(c)0001(d)0010#c
  9. What is the 2nd complement of 0001?#(a)1111(b)1110(c)0001(d)0010#a
  10. A circular left shift of 1010 by 1 position gives#(a)0101(b)1010(c)1111(d)1101#a
  11. The binary result of 4 AND 5 is#(a)100(b)101(c)001(d)000#a
  12. Which operation checks whether a bit is set?#(a)XOR(b)AND(c)OR(d)Shift Right#c
  13. Right-shifting 16 by 2 results in#(a)2(b)4(c)8(d)16#b
  14. The hexadecimal equivalent of binary 1110 is#(a)C(b)E(c)A(d)D#b
  15. Which bitwise operation clears a specific bit?#(a)AND with 0(b)XOR(c)OR(d)NOT#a
  16. Which operation flips all bits?#(a)AND(b)OR(c)NOT(d)XOR#c
  17. XORing any number with itself results in#(a)The same number(b)0(c)1(d)Its complement#b
  18. What is the decimal equivalent of binary 1011?#(a)9(b)10(c)11(d)12#c
  19. The binary result of NOT 0000 is#(a)1111(b)0000(c)1000(d)0101#a
  20. The result of XORing 0101 and 1010 is#(a)0000(b)1111(c)1010(d)1100#b
  21. How many distinct values can be represented by 4 bits?#(a)8(b)16(c)4(d)32#b
  22. A logical left shift of 0010 by 2 positions results in#(a)0100(b)1000(c)1100(d)1010#b
  23. What does right-shifting a signed number fill the vacant bits with?#(a)0(b)1(c)Sign bit(d)Random bits#c
  24. What does the OR operation between two bits yield?#(a)1 if both are 1(b)0 if both are 0(c)1 if either is 1(d)1 if both are 0#b
  25. The binary result of 8 OR 4 is#(a)1111(b)1100(c)1000(d)1100#b
  26. The binary result of XORing 1100 and 1010 is#(a)0110(b)1110(c)0000(d)0011#a
  27. A bit mask is used to#(a)Toggle specific bits(b)Check specific bits(c)Set specific bits(d)All of the above#d
  28. The 2nd complement of binary 1010 is#(a)0110(b)0101(c)1010(d)0111#a
  29. The operation to set a specific bit to 1 is#(a)AND(b)XOR(c)OR(d)NOT#c
  30. A left shift of binary 0011 by 3 positions results in#(a)11000(b)1100(c)1000(d)0110#a
  31. What is the result of NOT 1111?#(a)1111(b)0000(c)0001(d)1000#b
  32. The binary representation of decimal 7 is#(a)0110(b)0111(c)1000(d)0101#b
  33. The result of XORing 1111 and 1010 is#(a)0101(b)1010(c)1100(d)0000#a
  34. What is the decimal equivalent of binary 1100?#(a)11(b)12(c)13(d)14#b
  35. What does ANDing a number with its complement yield?#(a)All bits 1(b)All bits 0(c)The same number(d)The opposite number#b
  36. A circular right shift of 1101 by 2 positions gives#(a)1110(b)0111(c)1011(d)0110#c
  37. Which bitwise operation can be used to invert specific bits?#(a)OR(b)XOR(c)AND(d)NOT#b
  38. The 1st complement of 1000 is#(a)0111(b)1001(c)1111(d)0000#a
  39. What does XORing with 1 do to a bit?#(a)Inverts it(b)Sets it to 1(c)Clears it(d)Does nothing#a
  40. What is the binary result of ANDing 1001 and 1100?#(a)1000(b)1100(c)0001(d)0100#a
  41. Which operation is used to check if a number is odd?#(a)AND with 1(b)OR with 1(c)XOR with 1(d)NOT#a
  42. The hexadecimal equivalent of binary 11111111 is#(a)FF(b)0F(c)F0(d)AA#a
  43. The result of ORing 1001 and 0101 is#(a)1110(b)1001(c)1101(d)0100#c
  44. A left shift by 1 bit is equivalent to#(a)Adding 1(b)Subtracting 1(c)Multiplying by 2(d)Dividing by 2#c
  45. What is the result of XORing 1010 and 1010?#(a)0000(b)1010(c)1111(d)0101#a
  46. The binary result of NOT 0011 is#(a)1100(b)0011(c)1111(d)1001#a
  47. How many bits are in a byte?#(a)2(b)4(c)8(d)16#c
  48. Which operation can be used to clear all bits?#(a)XOR with 0(b)AND with 0(c)OR with 1(d)Shift Right#b
  49. The binary result of 4 OR 8 is#(a)1100(b)0100(c)1010(d)1000#a
  50. The complement of 0101 is#(a)1010(b)0101(c)1111(d)0000#a
  51. The binary result of 3 AND 5 is#(a)0001(b)0011(c)0101(d)0110#a
  52. A right shift by 1 bit is equivalent to#(a)Dividing by 2(b)Multiplying by 2(c)Adding 1(d)Subtracting 1#a
  53. The binary equivalent of decimal 15 is#(a)1111(b)1110(c)1100(d)1010#a
  54. The result of XORing 1110 and 1001 is#(a)0111(b)1111(c)1000(d)0000#a
  55. What is the 2nd complement of binary 0101?#(a)1011(b)1010(c)1101(d)0110#a
  56. What does a circular left shift of 1011 by 2 produce?#(a)1110(b)0111(c)1101(d)1011#a
  57. What does right-shifting a binary number by 3 do?#(a)Divide by 8(b)Multiply by 8(c)Divide by 3(d)Multiply by 3#a
  58. The result of ORing 1100 and 0011 is#(a)1111(b)1001(c)1100(d)1010#a
  59. Which operation flips all bits in a binary number?#(a)NOT(b)XOR(c)OR(d)AND#a
  60. What is the binary equivalent of decimal 9?#(a)1010(b)1001(c)1101(d)1110#b
  61. The binary result of XORing 1010 and 0101 is#(a)1111(b)1000(c)1010(d)0000#a
  62. A logical AND operation is equivalent to#(a)Multiplication(b)Addition(c)Division(d)Subtraction#a
  63. The binary representation of decimal 6 is#(a)0101(b)0110(c)1000(d)1011#b
  64. Which operation sets a bit to 1 without affecting other bits?#(a)OR(b)XOR(c)AND(d)NOT#a
  65. The result of NOT 0001 is#(a)1110(b)0000(c)1111(d)0010#a
  66. A left shift of binary 0101 by 2 positions results in#(a)1010(b)0011(c)1100(d)0001#c
  67. What is the decimal equivalent of binary 1001?#(a)7(b)8(c)9(d)10#c
  68. The hexadecimal representation of binary 1010 is#(a)F(b)A(c)B(d)E#b
  69. How many values can a 2-bit binary number represent?#(a)4(b)2(c)8(d)16#a
  70. Which operation clears a specific bit to 0?#(a)AND with 0(b)XOR(c)OR(d)NOT#a
  71. The binary result of ANDing 1111 and 1100 is#(a)1100(b)1111(c)0000(d)1001#a
  72. A circular right shift of binary 1001 by 1 gives#(a)1100(b)1110(c)0100(d)1100#a
  73. What is the result of XORing 1100 and 1100?#(a)1111(b)1010(c)0000(d)0111#c
  74. The result of NOT 0110 is#(a)1001(b)0111(c)1010(d)1101#a
  75. The 1st complement of binary 1101 is#(a)0101(b)0010(c)1011(d)0110#b
  76. A left shift operation by 2 bits is equivalent to#(a)Multiply by 2(b)Divide by 2(c)Multiply by 4(d)Divide by 4#c
  77. The binary equivalent of decimal 12 is#(a)1101(b)1110(c)1100(d)1010#c
  78. Which operation is used to check a specific bit in a number?#(a)XOR(b)AND(c)OR(d)NOT#b
  79. The result of ORing 1000 and 1001 is#(a)1101(b)1001(c)1110(d)1000#b
  80. A right shift by 3 bits is equivalent to#(a)Dividing by 4(b)Dividing by 8(c)Multiplying by 4(d)Adding 3#b
  81. The binary result of 7 AND 3 is#(a)0001(b)0011(c)0101(d)0110#b
  82. A left shift of binary 1010 by 3 positions results in#(a)10000(b)1010000(c)10110(d)01010#b
  83. The 2nd complement of binary 0110 is#(a)1010(b)1001(c)1110(d)1011#a
  84. What is the result of XORing binary 1111 and 0000?#(a)1111(b)0000(c)1010(d)1100#a
  85. A circular left shift of binary 1001 by 1 position gives#(a)1110(b)1010(c)1100(d)0011#d
  86. Which operation can isolate the least significant bit of a binary number?#(a)AND(b)XOR(c)NOT(d)OR#a
  87. The binary result of NOT 1010 is#(a)1111(b)1101(c)0101(d)0111#c
  88. A logical OR operation outputs 1 when#(a)Both inputs are 0(b)Both inputs are 1(c)Either input is 1(d)Neither input is 1#c
  89. The hexadecimal equivalent of binary 1111 is#(a)E(b)F(c)A(d)C#b
  90. The binary representation of decimal 18 is#(a)10010(b)10101(c)11001(d)11100#a
  91. What is the decimal equivalent of binary 1110?#(a)12(b)13(c)14(d)15#c
  92. The result of ANDing binary 1010 and 0110 is#(a)0010(b)0111(c)1110(d)1010#a
  93. The 1st complement of binary 1000 is#(a)0111(b)1100(c)1110(d)1011#a
  94. A left shift of binary 0011 by 2 results in#(a)1111(b)0110(c)1100(d)1000#c
  95. The binary equivalent of decimal 20 is#(a)10100(b)10010(c)11010(d)11100#a
  96. Which operation toggles a specific bit in a binary number?#(a)XOR(b)OR(c)AND(d)NOT#a
  97. The binary result of XORing 1100 and 1010 is#(a)0110(b)1000(c)1111(d)0101#a
  98. What is the result of ORing binary 0000 and 1111?#(a)0000(b)1010(c)1111(d)0110#c
  99. A circular right shift of binary 0110 by 1 results in#(a)0011(b)0111(c)1110(d)1011#a
  100. The result of NOT 1111 is#(a)0000(b)0110(c)1010(d)0001#a
  101.  
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