FreeBSD: output from a suggested vmstat command

It is possible to measure the resident memory set:

$ vmstat -o | awk 'NR>1 { t[$7] += $1 } \
END { for (i in t) printf "%s %d\n",i,t[i] }'

The rows have the following meaning:
df = default (not assigned a specific pager)
sw = swap
df = virtual
vn = vnode
ph = heap
md = memory device

This will be reported in number of pages, so it needs to be multiplied by the
page size of the architecture which can be found via:

$ sysctl -n hw.pagesize

                -- Daniel Ebdrup Jensen <[email protected]>
% su -
Password:
root@mowa219-gjp4-8570p-freebsd:~ # sh
# vmstat -o | awk 'NR>1 { t[$7] += $1 } \
> END { for (i in t) printf "%s %d\n",i,t[i] }'
 0
dv 4
vn 205016
ph 905
review 0
md 7551
sw 1098641
# exit
root@mowa219-gjp4-8570p-freebsd:~ # sysctl -n hw.pagesize
4096
root@mowa219-gjp4-8570p-freebsd:~ # sh
# vmstat -o | awk 'NR>1 { t[$7] += $1 } \
END { for (i in t) printf "%s %d\n",i,t[i] }'
 0
dv 4
vn 204191
ph 905
review 0
md 7583
sw 1106698
#