Pythagorean triples

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;

int main() {
    ll n; cin >> n;
    if (n <= 2) cout << -1;
    else if (n % 2 == 0)
    {
        cout << n*n/4 - 1 << " " << n*n/4 + 1;
    } else
    {
        cout << (n*n+1)/2 - 1 << " " << (n*n+1)/2;
    }
    return 0;
}