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Step 1
a.

The given structural formula of the compound:



Above compound contains 4 carbon atoms in its main chain.

Numbering will be started from the end which is closer to the substituent.

Position 1,2,3,4 has a hydroxyl groups each.



Name of the above compound is butane-1, 2, 3, 4-tetraol.

Step 2
b.

Recall the given structural formula of the compound:



Above compound contains 3 carbon atoms in its main chain.

Numbering will be started from the end which is closer to the substituent.

Position 2 has an enolate group.



Name of the above compound is potassium 2-methylpropan-2-olate.

Step 3
c.

Recall the given structural formula of the compound:



Simplified form of the compound is drawn above.

Above compound contains 6 carbon atoms in cyclic arrangements.

Numbering will be started from the carbon which contains more prior group hydroxyl group (-OH).

Position 2, 4, 6 has a chloro group each.

Position 3, 5 has one hydrogen atom each.

It suggests that it is a benzene ring. Presence of hydroxyl group (-OH) suggests that it is a phenol derivative.



Name of the above compound is 2, 4, 6-trichlorophenol.

Step 4
d.

Recall the given structural formula of the compound:



Above compound contains 3 carbon atoms in cyclic arrangements.

Numbering will be started from the carbon which contains more prior group hydroxyl group (-OH).

Position 1 has one hydroxyl group (-OH) and one methyl group.



Step 5
Name of the above compound is 1-methylcyclopropanol.
e.

Recall the given structural formula of the compound:



Above compound contains 6 carbon atoms in cyclic arrangements.

Numbering will be started from the carbon which contains more prior group hydroxyl group (-OH).

Position 2, has a bromo group each.

Above compound contains a benzene ring. Presence of hydroxyl group (-OH) suggests that it is a phenol derivative.



Name of the above compound is 2-bromophenol.

Step 6
f.

Recall the given structural formula of the compound:



Above compound contains 4 carbon atoms in cyclic arrangements.

Numbering will be started from the carbon which contains more prior group hydroxyl group (-OH).

Position 2, has a methyl group.

More prior group appears at the end of the nomenclature.



Name of the above compound is trans-2-methylcyclobutanol.

Step 7
g.

Recall the given structural formula of the compound:



Above compound contains 4 carbon atoms in its main chain.

Numbering will be started from the end which is closer to the substituent hydroxyl group.

Position 1has a hydroxyl groups and 2 has a double bond.

More prior group appears at the end of the nomenclature. Priority of hydroxyl group is greater than double bond.



Name of the above compound is but-2-en-1-ol.

Step 8
h.

Recall the given structural formula of the compound:



Simplified structural formula is drawn above.

Above compound contains 4 carbon atoms in its main chain.

Numbering will be started from the end which is closer to the substituent thiol group (-SH). Position has a thiol group.



Name of the above compound is butane-2-thiol.

Step 9
i.

Let us draw the given compound:



Above compound contains 4 carbon atoms in main chain.

Numbering will be started from the end which is closer to functional group -OH.



Position 2 contains a hydroxyl group.

Name of the above compound is butan-2-ol.

Step 10
j.

Let us draw the given compound:



Above compound contains 4 carbon atoms in main chain.

Numbering will be started from the end which is closer to substituent group.



Position 2 contains a hydroxyl group and a methyl group; position 3 contains a bromo group.

More prior group appears at the last in the nomenclature.

Hydroxyl group (-OH) has greater priority than methyl or bromo groups.

Name of the above compound is 3-bromo-2-methylbutan-2-ol.