02. Equal Sums Even Odd Position

#include <iostream>

using namespace std;

int main() {

    int startNum, endNum;
    cin >> startNum >> endNum;

    for (int i = startNum; i <= endNum; i++) {

        int odd = 0, even = 0, digit = i;

        for (int x = 0; x < 6; x++) {
            if (x % 2 == 0) {
                even += digit % 10;
            }
            else {
                odd += digit % 10;
            }
            digit /= 10;
        }

        if (odd == even) {
            cout << i  << " ";
        }
    }

    return 0;
}


РЕШЕНИЕ С to_string():

#include <iostream>
#include <string>

using namespace std;

int main() {

    int startNum, endNum;
    cin >> startNum >> endNum;

    for (int i = startNum; i <= endNum; i++) {

        int odd = 0, even = 0, digit = 0;

        string current = to_string(i);

        for (int x = 0; x < current.length(); x++) {
            int digit = (int)(current[x]);

            if (x % 2 == 0) {
                even += digit;
            }
            else {
                odd += digit;
            }
        }

        if (odd == even) {
            cout << i  << " ";
        }
    }

    return 0;
}