FizzBuzz with inline ifs

/*
FizzBuzz for the modern age.
Plays the age old classic game fizzbuzz between 1 and 100.
The rules are as follows.
If a number is a multiple of 3 then print "Fizz".
If a number is a multiple of 5 then print "Buzz".
If a number is a multiple of both 3 and 5 then print "FizzBuzz".
If a number is not a multiple of 3 nor a multiple of 5 print the
number.
Each out put should be on a new line.

This example requires c++11 or higher, due to the use of to_string,
although it could be simply adapted to work with older standards.
The example also makes use of in-line if statements, this may or not
be favoured by everyone, but I like them.

Copyright (c) 2014 Morgan Hill <morgan@pcwizzltd.com>

This program is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.

This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
GNU General Public License for more details.

You should have received a copy of the GNU General Public License
along with this program.  If not, see <http://www.gnu.org/licenses/>.

*/
#include <iostream>
#include <string>

using namespace std;
int main (){
    for (int i = 1; i<=100; ++i){
        string output = "";
        output += i % 3 == 0 ? "Fizz":"";
        output += i % 5 == 0 ? "Buzz":"";
        output += output.length() == 0 ? to_string(i):"";
        cout << output << endl;
    }
    return 0;
}