A. Часть 1. Самый прибыльный месяц

import numpy as np
import calendar
months_list = [calendar.month_name[i] for i in range(1, 13)]

class InconsistentDataError(Exception):
    pass

def get_most_profitable_month_name(
    amounts_of_sold_subscriptions: np.ndarray,
    subscriptions_prices: np.ndarray,
) -> str:
    if amounts_of_sold_subscriptions.shape[1] != subscriptions_prices.shape[1]:
        raise InconsistentDataError
    income = amounts_of_sold_subscriptions * subscriptions_prices
    sold_per_month = np.sum(income, axis = 1)
    max_id = np.argmax(sold_per_month)
    return months_list[max_id]