Drink the Water after Separating the Substance

Given a two-dimensional array representation of a glass of mixed liquids, sort the array such that the liquids appear in the glass based on their density. (Lower density floats to the top). If there are disproportinate number of substance then some of substances mixed together but a very low amount. The width of the glass will not change from top to bottom.

======================
|   Density Chart    |
======================
| Honey   | H | 1.36 |
| Water   | W | 1.00 |
| Alcohol | A | 0.87 |
| Oil     | O | 0.80 |
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Such as:

[['W', 'A', 'A', 'W', 'W', 'W', 'O', 'W', 'W', 'A'],
 ['A', 'H', 'O', 'O', 'H', 'O', 'H', 'A', 'H', 'W'],
 ['A', 'H', 'H', 'H', 'H', 'O', 'W', 'W', 'A', 'W'],
 ['H', 'A', 'A', 'H', 'O', 'A', 'H', 'W', 'O', 'A'],
 ['H', 'W', 'H', 'A', 'W', 'W', 'A', 'H', 'A', 'O'],
 ['A', 'W', 'H', 'W', 'H', 'O', 'A', 'A', 'A', 'W'],
 ['A', 'H', 'O', 'H', 'H', 'H', 'O', 'W', 'A', 'H'],
 ['A', 'W', 'W', 'H', 'H', 'W', 'A', 'A', 'A', 'A']]
=====================================================
                   ||
                   ||
                   \/
===================================================
 [['O', 'O', 'O', 'O', 'O', 'O', 'O', 'O', 'O', 'O'],
 ['O', 'A', 'A', 'A', 'A', 'A', 'A', 'A', 'A', 'A'],
 ['A', 'A', 'A', 'A', 'A', 'A', 'A', 'A', 'A', 'A'],
 ['A', 'A', 'A', 'A', 'A', 'A', 'W', 'W', 'W', 'W'],
 ['W', 'W', 'W', 'W', 'W', 'W', 'W', 'W', 'W', 'W'],
 ['W', 'W', 'W', 'W', 'W', 'W', 'W', 'H', 'H', 'H'],
 ['H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'H'],
 ['H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'H']]


#Solution using bubble sort
def separate_liquids(glass):
    if not glass: #if empty glass is given, return empty array
        return []
    glass2=glass
    glass2=sum(glass2,[])
    #replace the list item with int for sorting
    for n,i in enumerate(glass2):
        if i=='A':
            glass2[n]=0.87
        elif i=='H':
            glass2[n]=1.36
        elif i=='W':
            glass2[n]=1.00
        else:
            glass2[n]=0.80
     #bubble sort
    for i in range(len(glass2)-1,0,-1):
        for j in range(i):
            if glass2[j] > glass2[j + 1]:
                temp = glass2[j]
                glass2[j] = glass2[j + 1]
                glass2[j + 1] = temp

    char={1.36:'H',1.00:'W',0.87:'A',0.80:'O'}
    glass3=[char.get(x,x) for x in glass2]
    result = [glass3[x:x + len(glass[0])] for x in range(0, len(glass3), len(glass[0]))][:len(glass)]
    return result