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michael_xgrind

Exemplo de Swith case

Sep 5th, 2014
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C 0.81 KB | None | 0 0
  1. #include "stdio.h"
  2. #include "stdlib.h"
  3.  
  4. main() {
  5.     float num1= 0, num2 = 0;
  6.  
  7.     printf("Entre com o numero 1: ");
  8.     scanf("%f", &num1);
  9.     printf("Entre com o numero 2: ");
  10.     scanf("%f", &num2);
  11.  
  12.     int opcao = 0;
  13.  
  14.     printf("\nO que deseja fazer? \n");
  15.     printf("1) + , 2) - , 3) * , 4) /\n-> ");
  16.     scanf("%d", &opcao);
  17.  
  18.     switch(opcao) {
  19.         case 1:
  20.             printf("\n\nTotal: %2.2f + %2.2f = %2.2f\n", num1, num2, num1+num2);
  21.             break;
  22.         case 2:
  23.             printf("\n\nTotal: %2.2f - %2.2f = %2.2f\n", num1, num2, num1-num2);
  24.             break;
  25.         case 3:
  26.             printf("\n\nTotal: %2.2f * %2.2f = %2.2f\n", num1, num2, num1*num2);
  27.             break;
  28.         case 4:
  29.             if (num2 == 0)
  30.                 printf("\n\nImpossivel calcular\n");
  31.             else
  32.                 printf("\n\nTotal: %2.2f / %2.2f = %2.2f\n", num1, num2, num1/num2);
  33.             break;
  34.     }
  35.    
  36.     system("pause");
  37.     return 0;
  38. }
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