Mobile Operator

#include <iostream>
#include <string>

using namespace std;

int main() {
    string year, type, net;
    cin >> year >> type >> net;

    int months;
    cin >> months;

    double sum = 0;

    if (type == "Small") {
        if (year == "one") {
            sum += 9.98;
        }
        else {
            sum += 8.58;
        }
    }
    else if (type == "Middle") {
        if (year == "one") {
            sum += 18.99;
        }
        else {
            sum += 17.09;
        }
    }
    else if (type == "Large") {
        if (year == "one") {
            sum += 25.98;
        }
        else {
            sum += 23.59;
        }
    }
    else if (type == "ExtraLarge") {
        if (year == "one") {
            sum += 35.99;
        }
        else{
            sum += 31.79;
        }
    }

    if (net == "yes") {
        if (sum <= 10) {
            sum += 5.50;
        }
        else if (sum > 10 && sum <= 30) {
            sum += 4.35;
        }
        else {
            sum += 3.85;
        }
    }

    double total = sum * months;

    if (year == "two") {
        total -= 3.75 * total / 100;
    }

    printf("%.2f lv.\v", total);

    return 0;
}


Решение с тернарен оператор:

#include <iostream>
#include <string>

using namespace std;

int main() {
    string year, type, net;
    cin >> year >> type >> net;

    int months;
    cin >> months;

    double sum =
        type == "Small" ? (year == "one" ? 9.98 : 8.58) :
        type == "Middle" ? (year == "one" ? 18.99 : 17.09) :
        type == "Large" ? (year == "one" ? 25.98 : 23.59) :
        type == "ExtraLarge" ? (year == "one" ? 35.99 : 31.79) : 0;

    sum += net == "yes" ? (sum > 30 ? 3.85 : sum > 10 ? 4.35 : 5.50) : 0;

    double total = sum * months;

    if (year == "two") {
        total -= 3.75 * total / 100;
    }

    printf("%.2f lv.\v", total);

    return 0;
}