04. Fishing Boat

Решение с тернарен оператор:

#include <iostream>

using namespace std;

int main() {
    double budget;
    cin >> budget;

    string season;
    cin >> season;

    int personCount;
    cin >> personCount;

    const int SEASON_PRICE =
        season == "Winter" ? 2600 :
        season == "Spring" ? 3000 : 4200;

    const double PERSON_COUNT_DISCOUNT =
        personCount > 11 ? 0.25 :
        personCount > 6 ? 0.15 : 0.10;

    double sum = SEASON_PRICE * (1 - PERSON_COUNT_DISCOUNT);

    if (personCount % 2 == 0 && season != "Autumn") {
        sum *= 0.95;
    }

    cout.setf(ios::fixed);
    cout.precision(2);

    if (budget >= sum) {
        cout << "Yes! You have " << budget - sum << " leva left." << endl;
    }
    else {
        cout << "Not enough money! You need " << sum - budget << " leva." << endl;
    }

    return 0;
}