06. Building (solutions with or not ternary operator)

#include <iostream>

using namespace std;

int main() {

    int floorCount, floorFlatCount;
    cin >> floorCount >> floorFlatCount;

    string appendix;

    for (int f = floorCount; f > 0; f--) {
        if (f == floorCount) {
            appendix = "L";
        }
        else if (f % 2 == 1) {
            appendix = "A";
        }
        else {
            appendix = "O";
        }

        for (int n = 0; n < floorFlatCount; n++) {
            cout << appendix << f << n << " ";
        }
        cout << endl;
    }

    return 0;
}

Решение с тернарен оператор:

#include <iostream>

using namespace std;

int main() {

    int floorCount, floorFlatCount;
    cin >> floorCount >> floorFlatCount;

    string appendix;

    for (int f = floorCount; f > 0; f--) {
        appendix =
            f == floorCount ? "L" :
            f % 2 == 1 ? "A" : "O";

        for (int n = 0; n < floorFlatCount; n++) {
            cout << appendix << f << n << " ";
        }
        cout << endl;
    }

    return 0;
}