Love vs Friendship (Codewars)

'''

If　a = 1, b = 2, c = 3 ... z = 26

Then l + o + v + e = 54

and f + r + i + e + n + d + s + h + i + p = 108

So friendship is twice stronger than love :-)

The input will always be in lowercase and never be empty.



'''

alphabet = "abcdefghijklmnopqrstuvwxyz"

def lexarithm(word):

    # Create the map/directory
    directory = {}
    counter = 0
    for i in range(0, len(alphabet)):
        counter += 1
        directory[alphabet[i]] = counter

    # print(directory)
    # Directory is ready, time for scanning the parameter "word"
    weights = []
    for i in range(0, len(word)):
        # For every character of the word, "word[i]"
        for key, value in directory.items():
            if word[i] == key:
                weights.append(value)
                break

    # The list "weights" contains the equivalent numbers matching with the letters of word
    sum = 0
    for i in range(0, len(weights)):
        sum += weights[i]

    return sum

# MAIN FUNCTION
print(lexarithm("love"))
print(lexarithm("friendship"))