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ScriptingCat

Open File

Oct 22nd, 2022
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C# 0.89 KB | None | 0 0
  1. OpenFileDialog opendialogfile = new OpenFileDialog();
  2.             opendialogfile.Filter = "Lua File (*.lua)|*.lua|Text File (*.txt)|*.txt";
  3.             opendialogfile.FilterIndex = 2;
  4.             opendialogfile.RestoreDirectory = true;
  5.             if (opendialogfile.ShowDialog() != DialogResult.OK)
  6.                 return;
  7.             try
  8.             {
  9.                 fastColoredTextBox1.Text = "";
  10.                 System.IO.Stream stream;
  11.                 if ((stream = opendialogfile.OpenFile()) == null)
  12.                     return;
  13.                 using (stream)
  14.                     this.fastColoredTextBox1.Text = System.IO.File.ReadAllText(opendialogfile.FileName);
  15.             }
  16.             catch(Exception ex)
  17.             {
  18.                 int num = (int)MessageBox.Show("An unexpected error has occured", "OOF!", MessageBoxButtons.OK, MessageBoxIcon.Information);
  19.  
  20.             }
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