//Q2) Create an array of integers using dynamic memory allocation. Display the sum, all the integers and there respective addresses.

#include <iostream>
#include <stdlib.h>

using namespace std;

int main(){

    int n;
    cout<<"Enter the size of the array: ";
    cin>>n;
    int *arr=(int*)malloc(n*sizeof(int));
    cout<<endl;
    cout<<"Dynamically allocated memory of size: "<<sizeof(int)*n<<endl<<endl;

    cout<<"Enter the array elements: ";
    for(int i=0;i<n;i++){
        cin>>*(arr+i);
    }

    int sum=0;
    for(int i=0;i<n;i++){
        cout<<"arr["<<i<<"] = "<<*(arr+i) <<", &arr["<<i<<"] = "<<(arr+i)<<endl;
        sum=sum+(*(arr+i));
    }
    cout<<"Sum of all the array elements: "<<sum<<endl<<endl;
    free(arr);
    arr=NULL;
    cout<<"Memory released!!!"<<endl;

    return 0;
}
/*
    OUTPUT:

    Enter the size of the array: 5

    Dynamically allocated memory of size: 20

    Enter the array elements: 1 2 3 4 5
    arr[0] = 1, &arr[0] = 0x559908387ad0
    arr[1] = 2, &arr[1] = 0x559908387ad4
    arr[2] = 3, &arr[2] = 0x559908387ad8
    arr[3] = 4, &arr[3] = 0x559908387adc
    arr[4] = 5, &arr[4] = 0x559908387ae0
    Sum of all the array elements: 15

    Memory released!!!

*/