8 (кол-во слов с номером дел на 3 и доп условия)

#https://inf-ege.sdamgia.ru/problem?id=68241
alph = 'АЕКНРС'
sogl = 'СКНР'
cnt = 0
num = 1 #номер текущего слова
for q in alph:
    for w in alph:
        for e in alph:
            for r in alph:
                for t in alph:
                    for y in alph:
                        for u in alph:
                            for i in alph:
                                for o in alph:
                                    for p in alph:
                                        s = q + w + e + r + t + y + u + i + o + p
                                        if (num % 3 == 0) and (s[0] in sogl) and (s.count('Р') == 1):
                                            cnt += 1
                                        num += 1
print(cnt)