02. Exam Preparation

#include <iostream>
#include <string>

using namespace std;

int main() {
    int badGrades;
    cin >> badGrades;
    cin.ignore();

    string task, lastProblem;
    getline(cin, task);

    int badGradesCounter = 0, tasksCount = 0;
    double gradesTotal = 0, grade;

    while (task != "Enough") {
        cin >> grade;
        cin.ignore();

        gradesTotal += grade;
        tasksCount++;

        if (grade <= 4) {
            badGradesCounter++;

            if (badGradesCounter == badGrades) {
                printf("You need a break, %i poor grades.\n", badGradesCounter);
                break;
            }
        }

        lastProblem = task;
        getline(cin, task);
    }

    if (task == "Enough") {
        printf("Average score: %.2f\n", gradesTotal / tasksCount);
        printf("Number of problems: %i\n", tasksCount);
        printf("Last problem: %s\n", lastProblem.c_str());
    }

    return 0;
}

Решение с тернарен оператор:

#include <iostream>
#include <string>

using namespace std;

int main() {
    int badGrades;
    cin >> badGrades;
    cin.ignore();

    string task, lastProblem;
    getline(cin, task);

    int badGradesCounter = 0, tasksCount = 0;
    double gradesTotal = 0, grade;

    while (task != "Enough" && badGradesCounter != badGrades) {
        cin >> grade;
        cin.ignore();

        gradesTotal += grade;
        tasksCount++;

        if (grade <= 4) {
            badGradesCounter++;
        }

        lastProblem = task;
        getline(cin, task);
    }

    task == "Enough" ?
        printf("Average score: %.2f\nNumber of problems: %i\nLast problem: %s\n", gradesTotal / tasksCount, tasksCount, lastProblem.c_str()) :
        printf("You need a break, %i poor grades.\n", badGradesCounter);

    return 0;
}