Final Problem for 3

import time
import math
startingnumber = 0
endnumber = 100000000
startinterger=1
def threealterative(number):
    string = str(number)
    length = len(string)
    for i in range (length-2):
        if (string [i] == string[i+1]) and (string [i] == string [i+2]):
            return True
    return false

def dighitsthree(number):
    subs = [000,111,222,333,444,555,666,777,888,999]
    string = str(number)
    for sub in subs:
        if str(sub) in string:
            return true
    return false

time = time.clock()
for startinterger in range( 1,endnumber):
    if not threealterative(startinterger):
        startingnumber = startingnumber + (1/startinterger)
time2 = time.clock()
print (time.clock() - time, ' seconds ', endnumber, ' cycling')
print (startingnumber)

#250.32544094291302  seconds  100000000  cycling
#18.537367351280075

#http://www.tutorialspoint.com/python/python_date_time.htm
#https://docs.python.org/3.0/library/time.html
#https://pymotw.com/2/datetime/