Find Whether a Number is Armstrong or Not

class Armstrong
{
public static void main(String...s)
{
int m,n,i,j=0;
n=Integer.parseInt(s[0]);

m=n;
while(n!=0)
{
i=n%10;
j+=(i*i*i);
n/=10;
}

if(j==m)
System.out.println("\nNumber is armstrong");
else
System.out.println("\nNumber is not armstrong");
}
}