TASK_067 - AquaBlitz11's Solution

#include <bits/stdc++.h>
using namespace std;

const int N = 1010;

char s[N], t[N];
int cnt[26], cnt2[26];

int main()
{
    scanf("%s %s", s, t);
    for (int i = 0; s[i]; ++i)
        ++cnt[s[i]-'A'];
    for (int i = 0; t[i]; ++i)
        ++cnt2[t[i]-'A'];
    bool fail = false;
    for (int i = 0; i < 26; ++i) {
        if (cnt[i] != cnt2[i])
            fail = true;
    }
    if (fail) printf("No\n");
    else printf("Yes\n");

    return 0;
}