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FranzVuttke

can_it_be_arranged

Mar 25th, 2023 (edited)
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Python 0.32 KB | Source Code | 0 0
  1. def canItBeArranged(aChars:list, aTarget:str) -> bool:
  2.     probe = ""
  3.     for c in aTarget:
  4.         try:
  5.             ind = aChars.index(c)
  6.         except:
  7.             ind = -1
  8.         if ind > -1:
  9.             probe += aChars.pop(ind)
  10.         else:
  11.             break
  12.         # print(probe)
  13.  
  14.     return probe == aTarget
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