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pb_jiang

ABC280D WA

Dec 20th, 2022
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C++ 1.77 KB | None | 0 0
  1. #include <assert.h>
  2. #include <bits/stdc++.h>
  3. using namespace std;
  4. #define dbg(...) logger(#__VA_ARGS__, __VA_ARGS__)
  5. template <typename... Args> void logger(string vars, Args &&... values)
  6. {
  7.     cerr << vars << " = ";
  8.     string delim = "";
  9.     (..., (cerr << delim << values, delim = ", "));
  10.     cerr << endl;
  11. }
  12.  
  13. template <class T> inline auto vv(int m) { return vector<vector<T>>(m, vector<T>(m)); }
  14. template <class T> inline auto vv(int m, int n) { return vector<vector<T>>(m, vector<T>(n)); }
  15. template <class T, T init> inline auto vv(int m) { return vector<vector<T>>(m, vector<T>(m, init)); }
  16. template <class T, T init> inline auto vv(int m, int n) { return vector<vector<T>>(m, vector<T>(n, init)); }
  17.  
  18. template <class T> using mpq = priority_queue<T, vector<T>, greater<T>>;
  19. using vi = vector<int>;
  20. using ll = long long;
  21. using pii = pair<int, int>;
  22.  
  23. const int MAXN = 1e6 + 27;
  24. int not_prime[MAXN];
  25. ll prime[MAXN], pcnt = 0;
  26.  
  27. void seive()
  28. {
  29.     for (int i = 2; i < MAXN; ++i) {
  30.         if (!not_prime[i]) {
  31.             prime[pcnt++] = i;
  32.         }
  33.         for (int j = 0; j < pcnt && prime[j] * i < MAXN; ++j) {
  34.             not_prime[prime[j] * i] = 1;
  35.             if ((i % prime[j]) == 0)
  36.                 break;
  37.         }
  38.     }
  39. }
  40.  
  41. int main(int argc, char **argv)
  42. {
  43.     ll k;
  44.     cin >> k;
  45.     seive();
  46.     // dbg("after seive");
  47.     dbg(MAXN, prime[pcnt - 1]);
  48.  
  49.     map<ll, int> factor;
  50.     for (int i = 0; i < pcnt; ++i) {
  51.         while (k % prime[i] == 0) {
  52.             k = k / prime[i];
  53.             factor[prime[i]] += 1;
  54.         }
  55.     }
  56.     if (k != 1)
  57.         factor[k] += 1;
  58.     ll max_val = 1;
  59.     for (const auto &p : factor) {
  60.         max_val = max(max_val, p.first * p.second);
  61.     }
  62.     cout << max_val << endl;
  63.     return 0;
  64. };
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