5966 ПОЛЯКОВ

import itertools, math, re
mx = 2023**3

def chk3(n):
    s3 = ''
    while n > 0:
        s3 += str(n%3)
        n //= 3
    p = False
    lns3 = len(s3)
    for i in range(math.ceil(lns3/2)):
        if s3[i] != s3[lns3-i-1]:
            p = True
            break
    return p

def sum8(n):
    s = 0
    while n > 0:
        s += n % 8
        n //= 8
    return s

answer = list()

for n in range(1, 6):
    for s in itertools.product('0123456', repeat = n):
        if s[0] == '0':
            continue
        s = ''.join(s)
        t = int(s + s[::-1], 7)
        if t > mx:
            continue
        if chk3(t):
            continue
        if re.fullmatch(r'\d*2\d*0', str(t)):
            answer.append([t, sum8(t)])

for n in range(1, 6):
    for s in itertools.product('0123456', repeat = n):
        if s[0] == '0':
                continue
        s = ''.join(s)
        for k in range(0, 7):

            t = int(s + str(k) + s[::-1], 7)
            if t > mx:
                break
            if chk3(t):
                continue
            if re.fullmatch(r'\d*2\d*0', str(t)):
                answer.append([t, sum8(t)])


answer.sort()
for a in answer: print(a)