normal distribution

x1 = [30 35]; % pollutant released
x2 = [25 30];
x3 = [35 40];
x4 = [20 25];
x5 = [40 45];

mu = 33; % mean
sigma = 3; % standard deviation

Px1 = normspec(x1,mu,sigma); % probability of shaded area
Px2 = normspec(x2,mu,sigma);
Px3 = normspec(x3,mu,sigma);
Px4 = normspec(x4,mu,sigma);
Px5 = normspec(x5,mu,sigma);

Profit= 100*Px1 + 50*(Px2+Px3) - 60*(Px4+Px5); % Answer