Three brothers

#include <iostream>
#include <cmath>

using namespace std;

int main() {
    double firstTime, secondTime, thirdTime, fatherTime;
    cin >> firstTime >> secondTime >> thirdTime >> fatherTime;

    double cleaningTime = 1 / (1 / firstTime + 1 / secondTime + 1 / thirdTime) * 1.15;

    printf("Cleaning time: %.2f\n", cleaningTime);
    if (fatherTime > cleaningTime) {
        printf("Yes, there is a surprise - time left -> %.0f hours.\n", floor(fatherTime - cleaningTime));
    }
    else {
        printf("No, there isn't a surprise - shortage of time -> %.0f hours.\n", ceil(cleaningTime - fatherTime));
    }
    return 0;
}