Three brothers

function threeBrothers(input) {
    let firstTime = Number(input[0]);
    let secondTime = Number(input[1]);
    let thirdTime = Number(input[2]);
    let fatherTime = Number(input[3]);

    let cleaningTime = 1 / (1 / firstTime + 1 / secondTime + 1 / thirdTime) * 1.15;

    console.log(`Cleaning time: ${cleaningTime.toFixed(2)}`);
    if (fatherTime > cleaningTime) {
        console.log(`Yes, there is a surprise - time left -> ${Math.floor(fatherTime - cleaningTime)} hours.`);
    } else {
        console.log(`No, there isn't a surprise - shortage of time -> ${Math.ceil(cleaningTime - fatherTime)} hours.`);
    }
    return;
}