# Thanks for your suggestion.
# I improved the code to avoid the if loop.
# to reduce from O(log/n) to O(n2)


def directions(position, direction, matrix):
    row, col = position
    matrix[row][col] = "-"

    moves = {'up': (-1, 0),
             'down': (1, 0),
             'left': (0, -1),
             'right': (0, 1)}

    d_row, d_col = moves[direction]
    row = (row + d_row) % len(matrix[row])
    col = (col + d_col) % len(matrix[row])
    return row, col, matrix


def print_matrix(matrix):
    for row in matrix:
        print("".join(row))


rows = int(input())
fishing_area = []
captain, whirlpool, empty, passage, quota = "S", "W", "-", 0, 20
position = None

for row_ in range(rows):
    line = list(input())
    if captain in line:
        position = (row_, line.index(captain))
    fishing_area.append(line)

direction = input()

while direction != "collect the nets":
    n_row, n_col, fishing_area = directions(position, direction, fishing_area)
    new_position = n_row, n_col

    step = fishing_area[n_row][n_col]

    if step.isdigit():
        passage += int(step)

    if step == whirlpool:
        passage = 0
        print(f"You fell into a whirlpool! The ship sank and you lost the fish you caught. "
              f"Last coordinates of the ship: [{n_row},{n_col}]")
        exit()

    fishing_area[n_row][n_col] = captain
    position = new_position
    direction = input()

if passage >= quota:
    print(f"Success! You managed to reach the quota!")
else:
    print(f"You didn't catch enough fish and didn't reach the quota! You need {quota - passage} tons of fish more.")
if passage > 0:
    print(f"Amount of fish caught: {passage} tons.")

print_matrix(fishing_area)