Copy line 2 to line 15 [Intel 8086]

.8086
.model small
.stack 2048

dseg    segment para public 'data'
    line db 3;the line we will start copy
dseg    ends

cseg    segment para public 'code'
assume  cs:cseg, ds:dseg

Main  proc
    mov ax, dseg
    mov ds, ax
    mov ax,0b800h       ;B800 is the video memory adress
    mov es,ax           ;move that adress to es
                        ;es stands for "extra segment"

    mov cx, 2*80        ;2*80 we will copy 2 lines. Both with 80 columns
    xor bx, bx
    mov ax, 160         ;every video adress has a size of a word
                        ;so we need to jump 160 columns (theory)
    mov bl, line        ;then we want to start in third line, so multiply by three
    mul bl
    mov di, ax
    mov si, 15*160      ;this is to where we will copy the text. Line 15
    mov bl, 00100000b   ;[0][010][0000]b -> binary (*see below)
ciclo:
    mov bh, es:[di]     ;get the text from screen

    mov es:[si], bh     ;move the space to video adreess (in other words, write a space on screen)
    mov es:[si+1], bl   ;change color
    add di, 2           ;every video adress have a size of word, so let's add 2
    add si, 2
    loop ciclo          ;repeat until cx = 0, In every loop, cx is decremented


    mov ah,4CH
    int 21H
main    endp

cseg    ends
end     main

;the first 0 means static, if 1, text will be blinking
;the next 3 digits is for brackground color [000-111]
;the next 4 digits is for text color [000-1111]
;colors
;black          0000
;blue           0001
;gren           0010
;cyan           0011
;red            0100
;magenta        0101
;brown          0110
;light grey     0111
;dark grey      1000
;light blue     1001
;light green    1010
;light cyan     1011
;light red      1100
;light magenta  1101
;yellow         1110
;white          1111